Friction Acceleration: Solving for Coefficient and Force Angle

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To find the coefficient of kinetic friction for a 1000N crate pushed with a 300N force at a 20-degree angle below the horizontal, the net force and frictional force must be analyzed. The coefficient can be calculated using the equation f_friction = μ_k * N, where N is the normal force. If the force is pulling at a 20-degree angle above the horizontal, the acceleration of the crate can be determined by resolving forces and applying Newton's second law. The discussion emphasizes the importance of free body diagrams (FBD) in visualizing the forces at play. Understanding these concepts is crucial for solving friction-related problems in physics.
rogerbrian05
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A 1000N is being pushed across a level floor at a constant speed by a force of 300N at an angle of 20deg below the horizontal as shown in the figure below.
a. What is the coefficient of kinetic friction between the crate and the floor?
b. If the 300N Force is instead pulling the crate at an angle of 20deg above the horizontal as shown in the figure below, what will be the acceleration of the crate?




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The Attempt at a Solution

 
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Plot the diagram and FBD for starters.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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