Friction as centripetal force....problem with the mass

[Geo louv]

Homework Statement

The problem is that if I have a 5kg mass and 1 kg mass at the same radius with the same μ...and I increase slowly the angular speed ω...then the first mass that will stop the circular motion is the one of the 5 kg mass because needs more centripetal force.Can someone say that this is not true and the two objects will stop at the same time the circular motion because ofthe equations T=m(u^2)/r μΝ=m(u^2)/r μ(mg)=m(u^2)/r. μg=(u^2)/r. ?
2. Homework Equations

The Attempt at a Solution

 

[Geo louv]

I have big problem...because if you see the equation μg=u^2/r you can assume that the two objects will leave at the same time...

 

[deepakkumaar97]

.Can someone say that this is not true and the two objects will stop at the same time

This is not true.

 

[Geo louv]

Yes if you see the equation F=mω^2R...then you will come to the conclusion that the one with the bigger mass will stop first to moving circular because need more centripetal force.....Yes but also at the bigger mass I have bigger friction...T=μΝ. Τ=μ(mg)...so why two masses are not stopping the circular motion at the same time??

 

[deepakkumaar97]

They should stop at the same time.

 

[Geo louv]

No...if you do the experiment the bigger mass stop first the circular motion

 

[SammyS]

Homework Statement

The problem is that if I have a 5kg mass and 1 kg mass at the same radius with the same μ...and I increase slowly the angular speed ω...then the first mass that will stop the circular motion is the one of the 5 kg mass because needs more centripetal force.Can someone say that this is not true and the two objects will stop at the same time the circular motion because ofthe equations T=m(u^2)/r μΝ=m(u^2)/r μ(mg)=m(u^2)/r. μg=(u^2)/r. ?
2. Homework Equations

The Attempt at a Solution

This problem is not well defined. You haven't given enough details.

From the sparse description, I don't see how centripetal force is involved at all.

 

[Geo louv]

 

[Geo louv]

But m1 has also bigger friction...because of the bigger mass...so they must leave at the same time

 

[haruspex]

No...if you do the experiment the bigger mass stop first the circular motion

Please describe the experiment in detail. Are they both resting on a flat rotating surface, perhaps? What are the shapes and widths of the objects, and how far are their mass centres from the axis?

 

[Geo louv]

Haruspex you are GENIUS...OF course if it is a float rotating surface...they will stop rotation at the same time...,but if it's not...and the maximum Ts is the same then...the bigger mass will stop rotation first

 

[SammyS]

Haruspex you are GENIUS...OF course if it is a float rotating surface...they will stop rotation at the same time...,but if it's not...and the maximum Ts is the same then...the bigger mass will stop rotation first

Please describe the experiment in detail.