# Friction Cars Racing - 200m Race Results

• Intrusionv2
In summary, two cars are racing 200 meters to a stoplight, with one car having its coefficient of friction reduced to 0.07 due to oil on its tires. Assuming the first car does not slip, the first car will win by a distance of approximately 14 meters, as its acceleration will be 0.07 times that of the second car. This is based on the equations Ff = μ(Fn), a = μ(9.8), and Vf^2 = Vi^2 + 2a * x, with the static coefficient of friction of rubber on concrete being 1.0 and the kinetic coefficient being 0.8.
Intrusionv2

## Homework Statement

Two cars are going to begin at rest and race 200 meters to a stoplight. One driver sneaks over and puts oil on the other car's tires, which reduces it coefficient of friction to .07. Assuming the first car does not slip then by how much distance will it win?

## Homework Equations

Ff = μ(Fn)
a = μ(9.8)
Vf^2 = Vi^2 + 2a * x
Static coefficient of friction of rubber on concrete = 1.0
Kinetic coeff. of friction of rubber on concrete = 0.8

## The Attempt at a Solution

1st car:
Vf^2 = 2(.8*9.8)200
vf = 39.6 m/s

2nd car:
a = .07(9.8)
a = .686 m/s^2

vf^2 = 2(.686)
vf = 1.2 m/s

Not sure what to do now.

All things being equal for the first car then I'd say it's acceleration would be .07 of the second.

So for the unslicked car 200 = 1/2a*T2

The slicked car would only have gone only .07 (200) = 14 m in the same time.

I would like to clarify some points before providing a response to this content. First, it is important to specify the units used in the equations, as they are crucial for accurate calculations. Additionally, it is necessary to mention the mass of the cars and the type of tires used, as these factors can also affect the coefficient of friction and the cars' overall performance.

Now, to answer the question, assuming both cars have the same mass and are using the same type of tires, the first car will win the race by a distance of approximately 198.8 meters. This can be calculated by using the equations provided in the statement.

The first car's final velocity (vf) can be calculated using the equation Vf^2 = Vi^2 + 2a * x, where Vi is the initial velocity (0 m/s) and a is the acceleration (0.8 m/s^2). Plugging in these values, we get:

Vf^2 = 2(0.8)(200)
Vf^2 = 320
Vf = √320
Vf = 17.9 m/s

This means that the first car will reach a velocity of 17.9 m/s before reaching the stoplight. On the other hand, the second car's final velocity can be calculated using the same equation, but with a different acceleration value (0.686 m/s^2) due to the reduced coefficient of friction. Therefore, we get:

Vf^2 = 2(0.686)(x)
Vf^2 = 1.372x
Vf = √(1.372x)

Since both cars will reach the same final velocity (0 m/s) at the stoplight, we can set the two equations equal to each other:

17.9 = √(1.372x)
17.9^2 = 1.372x
320.41 = 1.372x
x = 233.7 m

This means that the second car will only travel a distance of 233.7 meters before reaching the stoplight. Therefore, the first car will win the race by a distance of approximately 198.8 meters (200 - 1.2 = 198.8 m).

In conclusion, the first car will win the race by a considerable margin due to the reduced coefficient of friction on the second car's tires. However, it

## 1. What is friction and how does it affect car racing?

Friction is the force that resists the motion of one surface against another. In car racing, friction plays a crucial role in determining how fast a car can move. Friction between the tires and the track surface helps the car to grip the track and accelerate, while too much friction can slow the car down.

## 2. How does the type of surface impact the results of a 200m race?

The type of surface can have a significant impact on the results of a 200m race. Different surfaces have varying levels of friction, which can affect how fast a car can move. For example, a smooth track with low friction may allow cars to move faster compared to a rough track with high friction.

## 3. Can the design of a car affect its performance in a 200m race?

Yes, the design of a car can greatly impact its performance in a 200m race. Factors such as the shape and weight distribution of the car can affect its aerodynamics and how well it can grip the track. A well-designed car can have a competitive advantage over a poorly designed one.

## 4. How do external factors like wind and temperature affect the results of a 200m race?

External factors such as wind and temperature can have a significant impact on the results of a 200m race. Strong winds can create drag on the car, slowing it down. On the other hand, warmer temperatures can cause the track surface to become more slippery due to a decrease in friction.

## 5. What role does the driver play in the results of a 200m race?

The driver plays a crucial role in the results of a 200m race. A skilled and experienced driver can make strategic decisions, such as choosing the best racing line and adjusting their speed, to optimize the car's performance and achieve a faster time. The driver's reaction time and ability to handle the car can also affect the results of the race.

• Introductory Physics Homework Help
Replies
18
Views
2K
• Introductory Physics Homework Help
Replies
20
Views
1K
• Introductory Physics Homework Help
Replies
20
Views
2K
• Introductory Physics Homework Help
Replies
3
Views
20K
• Introductory Physics Homework Help
Replies
1
Views
758
• Introductory Physics Homework Help
Replies
10
Views
4K
• Introductory Physics Homework Help
Replies
7
Views
3K
• Introductory Physics Homework Help
Replies
20
Views
2K
• Introductory Physics Homework Help
Replies
1
Views
2K
• Introductory Physics Homework Help
Replies
2
Views
2K