Solving Friction Fraction: Step-by-Step Guide

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Homework Help Overview

The problem involves two ramps at a 30-degree angle, one frictionless and the other with friction, where two blocks are pushed up the ramps with the same initial velocity. The block on the ramp with friction travels a fraction of the distance compared to the block on the frictionless ramp, and the task is to find the coefficient of sliding friction.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using work-energy principles and explore the relationship between the distances traveled by the blocks. Questions arise about the definitions of acceleration and the implications of canceling variables in their equations.

Discussion Status

Some participants have made progress in setting up equations based on energy conservation and are exploring the relationships between the variables. There is an indication of a productive direction as one participant notes a realization about how to incorporate the coefficient of friction into their equations.

Contextual Notes

Participants mention the need to consider multiple equations and the potential for variables to cancel out, which may lead to confusion. The problem's setup and the specific values given, such as the fraction of distance traveled, are central to the discussion.

Mivz18
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Here is the problem:

A student has two ramps both are at an angle of 30o. Ramp 1 is frictionless and ramp 2 has friction. The student also has two blocks, one for each ramp. She pushes the blocks up the ramps with the same initial velocity. The block on ramp 2 only travels a fraction f = 0.625 as far before coming to a stop as the block on ramp 1. Find the coefficient of sliding friction between the block and ramp 2.

How do I even begin this problem? I have found the forces of each of the blocks. I know that it will involve more than one equation and the canceling out of variables to find the unknown needed. But how?
 
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I think I would be inclined to use work-energy calculations. Both blocks start with the same amount of energy...
 
Well, this is a problem I've put aside a while, but still haven't been able to figure out. So far, I have discovered that Vo = Vo for both blocks on ramp 1 and 2. D1 = D and D2 = 0.625D .

Solving for A), Ramp 1

Vf ^ 2 = Vi ^2 + 2a(delta D)
0 = Vi ^2 + 2a(delta D)
0 = Vi^2 + 2aD

Solving for B), Ramp 2

Vf^2 = Vi^ 2 + 2a(delta D)
0 = Vi^2 + (2a)(0.625D)

Substituting and setting equations equal you get:

Vi1 ^2 + 2aD = Vi2^2 + (2a)(0.625D)
2aD = (2a)(0.625D)

From here, if I try to solve for one variable, both cancel out leaving me at a road block. Did I take a wrong detour in coming to where I am now? Or have I done something completely wrong?
 
Nevermind, I figured out where to go and how a1 and a2 were defined to cancel out the D variable and bring in the coefficient of friction variable.
 

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