Friction (horizontal) Applied Greater Force than Equilibrium

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SUMMARY

The discussion centers on calculating the horizontal force exerted by the floor on a block when a horizontal force of 50 N is applied. The block moves at a constant speed when a 44 N force is applied, indicating that the kinetic friction coefficient (μk) equals the static friction coefficient (μs). The frictional force can be determined using the equation ffriction ≈ μkFN, where FN represents the normal force. The key takeaway is that the horizontal component of the force exerted by the floor equals the applied force minus the frictional force, which is equal to the applied force when the block moves at constant speed.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with friction coefficients (μk and μs)
  • Knowledge of normal force (FN) calculations
  • Basic algebra for solving equations
NEXT STEPS
  • Study the relationship between normal force and frictional force in static and kinetic scenarios
  • Learn how to apply Newton's second law in horizontal motion problems
  • Explore examples of calculating frictional forces in various materials
  • Investigate the effects of different coefficients of friction on motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for examples of friction and force interactions in real-world applications.

PraetorGT
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Homework Statement


When you apply a horizontal force of 44 N o a block, the block moves across the floor at a constant speed (μk = μs). When you apply a force of 50 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?


Homework Equations


ffriction ≈ μkFN


The Attempt at a Solution



I'm not sure how to go about this. If the question asks for the horizontal force, do I still need to use the force of gravity in my calculations?

An explanation is appreciated, with or without the answer. I want to know how to do this, not necessarily know what the answer is.
 
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PraetorGT said:

Homework Statement


When you apply a horizontal force of 44 N o a block, the block moves across the floor at a constant speed (μk = μs). When you apply a force of 50 N, what is the magnitude of the horizontal component of the force that the floor exerts on the block?


Homework Equations


ffriction ≈ μkFN


The Attempt at a Solution



I'm not sure how to go about this. If the question asks for the horizontal force, do I still need to use the force of gravity in my calculations?

An explanation is appreciated, with or without the answer. I want to know how to do this, not necessarily know what the answer is.
The floor exerts both a perpendicular (Normal) force in the vertical y direction, and a friction force in the horizontal direction, opposite the relative motion between the block and floor. The book is looking for the horizontal force component of the floor on the block.
 

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