Friction with two stacked blocks and friction

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Homework Help Overview

The problem involves two stacked blocks, Block A and Block B, with given weights and a coefficient of kinetic friction. The objective is to determine the horizontal force required to drag Block B at constant speed while connected by a cord over a pulley. The context includes the application of Newton's laws and frictional forces.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss free body diagrams (FBDs) for both blocks and the forces acting on them, including normal forces, gravitational forces, tension, and friction. There is a focus on the equations derived from Newton's second law and the relationship between mass, acceleration, and force. Questions arise regarding the correct interpretation of the variables and the setup of the equations.

Discussion Status

Participants are actively engaging with the problem, clarifying the meaning of terms and equations. There is recognition of the need to address the number of equations versus unknowns, and some guidance has been offered regarding the implications of constant speed on acceleration.

Contextual Notes

There is a mention of the assumption that the blocks move at constant speed, which implies zero acceleration. Participants are also considering the effects of friction and the relationship between tension in the rope and the forces acting on the blocks.

EEintraining
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Homework Statement



Here is the problem:

Block A in the figure weighs 1.05 , and block B weighs 3.90 . The coefficient of kinetic friction between all surfaces is 0.32. Find the magnitude of the horizontal force necessary to drag block B to the left at constant speed if and are connected by a light, flexible cord passing around a fixed, frictionless pulley.See the attachment for a picture.

https://www.physicsforums.com/attachment.php?attachmentid=44607&stc=1&d=1330645523


Homework Equations



ƩFx=Max, Friction=uk*n

The Attempt at a Solution



My FBD for the upper block has N going up MG going down Fk going left and T going right (positive)

My FBD for lower has N going up MG going down (I included both weights) Tension and then both frictions going to the right, and the force required going to the left (which i made positive for this one)

I am not sure what i am missing in solving this. Help me see if I have the right set up please. For the bottem block I have:

Sum of forces in x = M*Ax

Pull - Tension - .32(4.95) -.32(1.05)= M*Ax

For the top block I have:

T-.32(1.05)=M*Ax

Am I correct for these equations, especially in the bottem block where I have subtracted both tensions, I am assuming this is correct because the table exerts friction but so would the top block as it is sliding across the top block.
 

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It is correct if you specify what M*Ax means in both equations.

ehild
 
M*Ax is mass * accel in the x direction from Newton 2

Sum of forces in x = mass time accel in x
 
Can you possibly point me in the direction of what i am missing... i have 3 equations with 2 unknowns right now.
 
EEintraining said:
M*Ax is mass * accel in the x direction from Newton 2

Sum of forces in x = mass time accel in x

Is it the same for both blocks??

ehild
 
EEintraining said:
Can you possibly point me in the direction of what i am missing... i have 3 equations with 2 unknowns right now.

You meant two equation with three unknowns, didn't you?

What do you know about the tension along a single rope ?

Do you know the acceleration if the blocks if they move along a straight line with constant speed?

ehild
 
Ehild thanks for your help yeah I did mean 2 eq and 3 unknown. After looking at this question that was exactly what I was was missing I must have read it too quickly constant speed tells me exactly what the acceleration is.
 
You are welcome. :smile:

ehild
 

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