1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

From rotational KE to translational displacement

  1. Feb 9, 2015 #1
    1. The problem statement, all variables and given/known data
    A frictionless pulley has the shape of a uniform solid disk of mass 5.00 kg and radius 28.0 cm . A 1.40 kg stone is attached to a very light wire that is wrapped around the rim of the pulley, and the stone is released from rest. As it falls down, the wire unwinds without stretching or slipping, causing the pulley to rotate. How far must the stone fall so that the pulley has 3.10 J of kinetic energy?
    Here's the given figure:
    1097738_001.jpg

    2. Relevant equations
    Rotational KE = (1/2) Iω2
    K1 + U1 = K2 + U2
    ν = rω
    a(tan)= dv/dt = r (dω/dt) = rα
    3. The attempt at a solution
    Part A: Forces doing work on the system? Gravitational force
    Part B:The magnitude of the velocity of the stone is the same as that of the point of contact.
    Part C: How far must the stone fall so that the pulley has 3.10 J of kinetic energy?
    I'm confused as to how I'm supposed to go from the above equations to finding linear displacement. Does this problem involve an integral of some kind?
    Thanks so much!
     
  2. jcsd
  3. Feb 9, 2015 #2

    Nathanael

    User Avatar
    Homework Helper

    If the pulley has a certain amount of kinetic energy, how much kinetic energy must the stone have?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: From rotational KE to translational displacement
  1. No translational KE? (Replies: 2)

Loading...