Function Composition: Simplifying f((f(t)-f(s))?

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SUMMARY

The discussion centers on the simplification of the expression f((f(t)-f(s))) where f is a function defined at points "s" and "t." Participants conclude that simplification is not possible, as demonstrated by the inequality f(t)-f(s) ≠ f(t-s) and the failure of f(f(t)-f(s)) to equal f(f(t))-f(f(s)). The example using the sine function illustrates the complexity of the expression, confirming that no straightforward composition exists.

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  • Understanding of function composition in mathematics
  • Familiarity with trigonometric functions, specifically sine
  • Knowledge of mathematical inequalities and their implications
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  • Research properties of trigonometric functions and their compositions
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Homework Statement



If [tex]f[/tex] is some function defined at points "s" and "t," is there any way to simplify the following expression?

[tex]f((f(t)-f(s))[/tex]

Homework Equations



None that I know of.

The Attempt at a Solution



I've been tinkering with this for a while and so far, I've determined the answer to be no. I know that

[tex]f(t)-f(s)\neq f(t-s)[/tex]

in general, and that implies that

[tex]f(f(t)-f(s))\neq f(f(t))-f(f(s))[/tex]

But does anyone know another way to simplify this to maybe some kind of composition?
 
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Let f(x)=sin x to give you a few ideas, I think the general answer is no.
 
[tex]sin(sin(t)-sin(s)) = [sin\circ sin(t)][cos\circ sin(s)] - [sin\circ sin(s)][cos\circ sin(t)][/tex]

Well that's a mess and a half. It is as I feared :redface:
 

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