Functions of more than one variable nomenclature

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SUMMARY

The discussion centers on the relationship between functions of one variable and functions of two variables, specifically in the context of differential equations. The equation y' = f(x, y) illustrates how y' is a function of both x and y, with f mapping the pair (x, y) to a specific expression, such as 2x + 3y. It is established that y(x) is distinct from f(x, y), emphasizing the complexity of their interrelation. The participants clarify that while y is dependent on x, the function f incorporates both variables simultaneously.

PREREQUISITES
  • Understanding of differential equations
  • Familiarity with functions of multiple variables
  • Knowledge of mathematical notation and terminology
  • Basic calculus concepts, particularly derivatives
NEXT STEPS
  • Study the properties of functions of multiple variables
  • Explore the method of solving first-order differential equations
  • Learn about the Jacobian matrix and its applications
  • Investigate the concept of partial derivatives and their significance
USEFUL FOR

Students of mathematics, particularly those studying calculus and differential equations, as well as educators seeking to clarify the distinctions between functions of one and two variables.

Calpalned
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Homework Statement


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Homework Equations


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The Attempt at a Solution


##y'=f(x.y)## is a function of two variables. ##y=y(x)## is a function of only one variable. How can they be related? Clearly ##y(x) = f(x) \neq f(x,y)##
Thanks
 
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Perhaps ##f(x) \neq y(x)##
 
Calpalned said:

Homework Statement


View attachment 90522

Homework Equations


n/a

The Attempt at a Solution


##y'=f(x.y)## is a function of two variables. ##y=y(x)## is a function of only one variable. How can they be related? Clearly ##y(x) = f(x) \neq f(x,y)##
Thanks
The right side of the differential equation y' = f(x, y) involves expressions in both x and y. For example, something like y' = 2x + 3y. Here f is a function that maps a pair of numbers (x, y) to 2x + 3y.

We generally assume that y is related to x in some way.
Calpalned said:
Perhaps ##f(x) \neq y(x)##
Correct.
 

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