Functions with multiple variables

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SUMMARY

The function f(x,y,z) = 1/(x^2+y^2+z^2) has a domain defined as R^3 excluding the origin, specifically represented as \mathbb{R}^3 \setminus{\{0,0,0\}} or alternatively as the set {(x,y,z) | x^2 + y^2 + z^2 ≠ 0}. This indicates that the function is undefined at the point (0,0,0) where the denominator equals zero. The discussion confirms the correct representation of the domain for this multivariable function.

PREREQUISITES
  • Understanding of multivariable functions
  • Knowledge of set notation in mathematics
  • Familiarity with the concept of domains in functions
  • Basic algebraic manipulation involving squares
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  • Study the properties of multivariable functions
  • Learn about domain restrictions in calculus
  • Explore set theory and its applications in mathematics
  • Investigate the implications of undefined points in functions
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Students studying multivariable calculus, mathematicians focusing on function analysis, and educators teaching concepts related to domains and functions in higher mathematics.

Niles
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Homework Statement



I have a function f(x,y,z) = 1/(x^2+y^2+z^2). I have to find the domain.
It is R^3, but x^2+y^2+z^2 != 0. How do I write that and am I correct?
 
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you're right. Think where are the points with x^2+y^2+z^2=0.
You can write the domain as: [tex]\mathbb{R}^3 \setminus{\{0,0,0\}}[/tex]
 
Or:
[tex]\{ (x,y,z)| x^2+ y^2+ z^2\ne 0 \}[/tex]
 

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