Fundamental Counting Principle Math problem

[ms. confused]

OK I'm unclear about how to use FCP to solve this problem:

The final score in a hockey game is 5-2. How many different scores are possible at the end of the second period?

 

[PRodQuanta]

OK I'm unclear about how to use FCP to solve this problem:

The FCP states that if you have all possible outcomes in a sample space can be found by multiplying the number of ways each event can occur. So, in your problem, you have 6 (outcomes 0,1,2,3,4,5) for one team's score, and 3 (outcomes 0,1,2) for the others. Multiply each possiblility by each other, and WHALAH.

Paden Roder

 

[wais]

To use the Fundamental Counting Principle for this problem, we need to break it down into smaller parts.

First, we know that there are two teams playing, so we can start by considering the number of possible scores for each team.

For the first team, they can score 0, 1, 2, 3, 4, or 5 goals in the second period. This means there are 6 possible scores for the first team.

For the second team, they can score 0, 1, or 2 goals in the second period. This means there are 3 possible scores for the second team.

To find the total number of possible scores, we multiply the number of scores for each team: 6 x 3 = 18.

Therefore, there are 18 different scores possible at the end of the second period in this hockey game.

Hope this helps clarify how to use the Fundamental Counting Principle for this problem!