(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 40-cm long string, with one end clamped and the other free to move transversely, is vibrating in its fundamental standing wave mode. If the wave speed is 320 cm/s, the frequency is:

A) 32 Hz

B) 16 Hz

C) 8 Hz

D) 4 Hz

E) 2 Hz

2. Relevant equations

[tex]v = \lambda[/tex][tex]f[/tex]

[tex]L = n(\frac{1}{2}\lambda)[/tex]

3. The attempt at a solution

[tex]L = n(\frac{1}{2}\lambda)[/tex]

[tex].40 = \frac{1}{2}\lambda[/tex]

[tex]\lambda = 0.8 [/tex]

[tex]v = \lambda[/tex][tex]f[/tex]

[tex] 3.2 = 0.8f[/tex]

[tex]f = 4[/tex]

Answer: E) 2 Hz

I'm wondering if perhaps the fact that the string is clamped on one end means that it would be like a sound tube that is closed on one end, and then I would have to use 1/4lambda instead of 1/2?

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# Homework Help: Fundamental standing wave problem

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