Fundamental theorem of calculus

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SUMMARY

The discussion focuses on evaluating the definite integral of the function (5y^(3/2) + 3y^(1/2)) from 1 to 4. The user attempted to compute the integral using the Fundamental Theorem of Calculus but arrived at an incorrect answer of 357/3 instead of the correct value of 76. Key mistakes included improper integration and misunderstanding the application of the power rule for integration. The correct approach involves accurately applying the power rule and evaluating the antiderivative at the bounds of integration.

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  • Understanding of the Fundamental Theorem of Calculus
  • Proficiency in integration techniques, specifically power rule for integration
  • Familiarity with evaluating definite integrals
  • Basic algebraic manipulation skills
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  • Review the Fundamental Theorem of Calculus and its applications
  • Practice integration using the power rule with various functions
  • Learn how to evaluate definite integrals step-by-step
  • Explore common mistakes in integration and how to avoid them
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staples82
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Homework Statement


Evaluate each definite integral.

ok I'm not sure how to do the integration sign, but... b=4, a=1 for (5yy^.5)+3y^.5)dy

Homework Equations


The Attempt at a Solution


I'm not really sure what I'm doing wrong.

i integrated...[tex]5y^2/2*y^(3/2)/(3/2)+3y^(3/2)/(3/2) <br /> <br /> then i plugged in stuff so...F(b)-F(a)...f(4)-(f1)<br /> <br /> I got (40*8/3+16)-(5/2*2/3+2) which gave me 357/3...the correct answer is 76 and I have no idea what I'm doing wrong, I've redone this problem 5 times and doublechecked to no avail :-([/tex]
 
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[tex]\int_1 ^{4}(5yy^\frac{1}{2} + 3y^\frac{1}{2})dy \equiv \int_1 ^{4}(5y^\frac{3}{2} + 3y^\frac{1}{2})dy[/tex]



Remember that y^m * y^n=y^(m+n)
 
rock.freak667 said:
[tex]\int_1 ^{4}(5yy^\frac{1}{2} + 3y^\frac{1}{2})dy \equiv \int_1 ^{4}(5y^\frac{3}{2} + 3y^\frac{1}{2})dy[/tex]



Remember that y^m * y^n=y^(m+n)

And remember that you need to use that rule, because you can't integrate a product by taking the product of the integrals.
 

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