# Fundamental theorem of calculus

1. Jul 5, 2008

### staples82

1. The problem statement, all variables and given/known data
Evaluate each definite integral.

ok I'm not sure how to do the integration sign, but... b=4, a=1 for (5yy^.5)+3y^.5)dy

2. Relevant equations

3. The attempt at a solution
I'm not really sure what i'm doing wrong.

i integrated...$$5y^2/2*y^(3/2)/(3/2)+3y^(3/2)/(3/2) then i plugged in stuff so...F(b)-F(a)...f(4)-(f1) I got (40*8/3+16)-(5/2*2/3+2) which gave me 357/3...the correct answer is 76 and I have no idea what I'm doing wrong, I've redone this problem 5 times and doublechecked to no avail :-( 2. Jul 5, 2008 ### rock.freak667 [tex]\int_1 ^{4}(5yy^\frac{1}{2} + 3y^\frac{1}{2})dy \equiv \int_1 ^{4}(5y^\frac{3}{2} + 3y^\frac{1}{2})dy$$

Remember that y^m * y^n=y^(m+n)

3. Jul 5, 2008

### Dick

And remember that you need to use that rule, because you can't integrate a product by taking the product of the integrals.

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