Fuse Wire Length and Capacity: A Discussion

Click For Summary
SUMMARY

The length of fuse wire does not influence its capacity, as confirmed by the discussion participants. The fuse capacity is determined by the temperature at which the wire melts, which is influenced by the power density dissipated in the wire rather than its length. The relevant equation is R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area. Ultimately, the temperature and thus the fuse capacity depend solely on the cross-sectional area of the wire.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the concept of power dissipation in electrical components
  • Knowledge of material properties such as resistivity
  • Basic grasp of thermal dynamics related to electrical components
NEXT STEPS
  • Research the relationship between power density and temperature in electrical conductors
  • Study the effects of cross-sectional area on electrical resistance
  • Explore the principles of fuse operation and thermal limits
  • Learn about different materials used in fuse wire and their properties
USEFUL FOR

Students studying electrical engineering, educators teaching physics concepts, and professionals involved in electrical safety and component design.

Vagrant
Messages
195
Reaction score
1

Homework Statement



does the length of the fuse wire influence its cpacity? why?

Homework Equations



R=pL/a

The Attempt at a Solution


My teacher said no. I think it should because R depends on L


Thanks for your time.
 
Physics news on Phys.org
shramana said:

Homework Statement



does the length of the fuse wire influence its cpacity? why?

Homework Equations



R=pL/a

The Attempt at a Solution


My teacher said no. I think it should because R depends on LThanks for your time.
I think I would agree with your teacher. The fuse capacity (the largest current permitted to flow) depends on the temperature of the fuse wire. At a certain temperature, it melts and stops the current. Off hand, I would say that the temperature depends upon the power density being dissipated in the fuse wire (power / unit volume). The power dissipated is [itex]I^2R = I^2\rho L/A[/itex]

Now, the power per unit volume is:

[tex]P/Vol = P/LA = I^2\rho L/A(LA) = I^2\rho/A^2[/tex]

So it appears to me that the L falls out and the temperature depends entirely upon the cross sectional area of the fuse wire.

AM
 
Thanks. I think your answer makes sense.
 

Similar threads

Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 30 ·
2
Replies
30
Views
3K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K