Galilean invariance (and Maxwell's equations)

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SUMMARY

The discussion centers on Galilean invariance and its relationship with Maxwell's equations. A Galilean transformation is defined, and it is established that the Maxwell equations are not covariant under such transformations, particularly when using the Lorentz gauge. The conversation references specific mathematical formulations, including the d'Alembertian operator and the potential form of Maxwell's equations. Key references are provided, highlighting historical perspectives and pedagogical implications of Galilean electromagnetism.

PREREQUISITES
  • Understanding of Galilean transformations and invariance
  • Familiarity with Maxwell's equations and their potential forms
  • Knowledge of the d'Alembertian operator in mathematical physics
  • Basic concepts of gauge theory in electromagnetism
NEXT STEPS
  • Study the implications of Galilean invariance in classical mechanics
  • Explore the Lorentz gauge and its effects on electromagnetic equations
  • Investigate the historical context of electromagnetism through the works of Jammer and Stachel
  • Learn about the formulation of Maxwell's equations using differential forms
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Physicists, electrical engineers, and students of electromagnetism seeking to deepen their understanding of the relationship between classical mechanics and electromagnetic theory.

quasar987
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Right or wrong? Specifically, an equation is said to be Galilean invariant if a substitution
x \rightarrow x \pm v_x t
y \rightarrow y \pm v_y t
z \rightarrow z \pm v_z t
t \rightarrow t
doesn't change the equation.
If right, would simply showing that
x \rightarrow x \pm vt
y \rightarrow y
z \rightarrow z
t \rightarrow t
do the trick too?
 
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Of course it would. We call that a "Galilean boost along the 'x' axis".

Daniel.
 
thanks you daniel, now the maxwell part of the thread...

Would a mathematical proof (i.e. not simply thought experiments implying moving magnets) that the Maxwell equations are not covariant be that

"The Maxwell equation in "potential form" under the Lorentz gauge of the scalar potential is

\nabla^2 V - \mu_0 \epsilon_0 \frac{\partial^2V}{\partial t^2} = -\frac{\rho}{\epsilon_0}

If I set V' = V(x', y', z', t') = V(x+vt, y, z, t) and calculate all the terms of this equation for V', I get...

\nabla^2 V' = \nabla '^2V

\frac{\partial^2V'}{\partial t^2}= v^2 \frac{\partial^2V}{\partial x' ^2}

\rho' = \rho'

so we see without reasembling the pieces that the equation is not the same"

?? And is there a simpler proof ?
 
It's good enough to me. It's all down to proving that the d'Alembertian is not Galilei invariant which you did.

Daniel.
 
I did?

I showed that the d'Alembertian applied to V' is not the same as the d'Alembertian applied to V, but not that \Box '^2V \neq \Box ^2V.
 
quasar987 said:
Would a mathematical proof (i.e. not simply thought experiments implying moving magnets) that the Maxwell equations are not covariant be that
"The Maxwell equation in "potential form" under the Lorentz gauge of the scalar potential is...
[snip]
First, to do this correctly, one has to really spell out what is meant by the "Maxwell Equations", as well as specify the field variables and their constitutive equations.

You may enjoy these:
"If Maxwell had worked between Ampere and Faraday:
An historical fable with a pedagogical moral"
Max Jammer and John Stachel
Am. J. Phy, v48, no 1, Jan 1980, pp 5-7

"Galilean Electromagnetism"
M. Le Bellac and J.M. Levy-Leblond
Il Nuovo Cimento, v14 B, no 2, April 1973, pp 217-233

"The fundamental equations of electromagnetism, independent of metrical geometry"
D. van Dantzig
Proc. Cambridge Phil. Soc., v 30, 1934a, pp 421-427

"Formal Structure of Electromagnetics: General Covariance and Electromagnetics"
E. J. Post, 1962 (in Dover).

(By the way, the above should not be mistaken for or associated with a journal entitled "Galilean Electrodynamics".)

Secondly, your demonstration isn't too convincing since you choose to demonstrate the failure of "Galilean" invariance by making use of the "Lorentz" gauge.
 
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I don't see what you mean. It failed under the Lorentz gauge, so that's all one need. No need to show it fails under other gauges. What would you think it takes to do a good demonstration?
 
quasar987 said:
I don't see what you mean. It failed under the Lorentz gauge, so that's all one need. No need to show it fails under other gauges. What would you think it takes to do a good demonstration?

As I said, I think that the problem has to be spelled out better. For example, there are "Maxwell equations" with E,B and equations with E,D,B,H. Using a potential formulation, you additionally deal with gauge issues. In addition, the way these fields transform have to be specified. (It may be that these "ground rules" are implicit in your problem.)

The references above point out that there is a way that the Galilean transformations can be compatible with a subset of electromagnetic phenomena, which has some pedagogical value. (See the Jammer/Stachel paper: http://aapt.scitation.org/doi/10.1119/1.12239. Here is the abstract: If one drops the Faraday induction term from Maxwell's equations, they become exactly Galilei invariant. This suggests that if Maxwell had worked between Ampère and Faraday, he could have developed this Galilei-invariant electromagnetic theory so that Faraday's discovery would have confronted physicists with the dilemma: give up the Galileian relativity principle for electromagnetism (ether hypothesis), or modify it (special relativity). This suggests a new pedagogical approach to electromagnetic theory, in which the displacement current and the Galileian relativity principle are introduced before the induction term is discussed. This reference may suggest one way to address your question.)

Note also the title of the van Dantzig paper, which formulates Maxwell equations using differential forms without the use of a metric, implying compatibility with either Galilean or Lorentz transformations.
 
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