Galileo's experiment and equivalence principle

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 2K views
AlonsoMcLaren
Messages
89
Reaction score
2
Why do we say that Galileo's experiment at Pisa is an illustration of Equivalence Principle?

All we know is that

G* (mass of earth)*(gravitational mass of object)/(R^2) = (intertial mass of object)*a

Therefore,
a=G* (mass of earth)*(gravitational mass of object)/(R^2 * (inertial mass of object))

The experiment shows that a does not change for different objects.
But this only guarantees that (gravitational mass of object)/(inertial mass of object)= a constant, which is not necessarily 1.
 
on Phys.org
AlonsoMcLaren said:
But this only guarantees that (gravitational mass of object)/(inertial mass of object)= a constant, which is not necessarily 1.

We choose the value of G so that that constant is equal to 1. We don't have to - it just makes the math simpler. We could, if we wanted, say that that constant was equal to 2, and use a value of G which was greater by a factor of four to make the calculation match the force that we measure experimentally ... but why bother?