Gauge pressure and mercury question

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SUMMARY

The discussion focuses on calculating gauge pressure at a depth of 6 cm in a glass containing 4 cm of mercury and 4 cm of water. The key formula used is P = ρgh, where ρ is the fluid density, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height of the fluid column. The gauge pressure is determined by considering the contributions from both the water and mercury layers, leading to the conclusion that the correct answer is 5.6 kPa, corresponding to option (b).

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  • Understanding of gauge pressure and its definition.
  • Knowledge of fluid density, specifically for water (1000 kg/m³) and mercury (13.6 times denser than water).
  • Familiarity with the formula for static pressure in fluids: P = ρgh.
  • Basic grasp of atmospheric pressure equivalencies (1 atm = 101.325 kPa).
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  • Study the concept of hydrostatic pressure in fluids.
  • Learn about the properties and applications of mercury in fluid mechanics.
  • Explore the relationship between gauge pressure and absolute pressure.
  • Investigate fluid statics and the implications of fluid density on pressure calculations.
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Students preparing for physics exams, educators teaching fluid mechanics, and anyone interested in understanding gauge pressure calculations in fluid systems.

stormnebula
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Gauge pressure question - please help

I came across this multiple choice question while revising for my exams but I can't get any of the chioces. I've spent over an hour on this but can't figure out. Can someone please help me because it's starting to annoy me.

What is the gauge pressure at a depth of 6cm in a glass filled with 4cm of mercury and 4cm of water? Water has a density of 1000kg/m^3, and mercury has a density 13.6 times as great.
(a)3.1kPa
(b)5.6kPa
(c)5.8kPa
(d)310kPa
(e)560kPa

Any help will be great.
 
Last edited:
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Gauge pressure is the absolute pressure minus the ambient pressure, so the problem asks for the pressure in the column simply due to the depth of the liquids.

One has 4 cm of Hg and 4 cm of water, but the problem asks for pressure at a depth of 6 cm (from the upper surface). Hg is denser to it has to be on the bottom.

So what is the pressure underneath 4 cm water and 2 cm Hg.

Static pressure in a fluid is given by:

P = \rho\,g\,h where \rho is fluid density, g = acceleration of gravity (~9.81 m/s2), and h is height of fluid.

Consider 1 atm = 14.7 lbf/in2 = 760 mm Hg = 101.325 kPa = (760x13.6) mm water.

Final the partial pressures due to depths of each fluid and that will be the gauge pressure.


See also - http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html#fp
 
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Thanks, I figured out the answer now. Your were a big help :smile:
 
I had the same question. Can you please go step by step on how you acquired the answer, because I don't understand how to "final" the different liquids and getting a gauge pressure.
 
Welcome to PF!

Hi Blackplague! Welcome to PF! :smile:

If you don't understand the formula, look at it this way …

https://www.physicsforums.com/library.php?do=view_item&itemid=80" = force/area

the gauge pressure at the bottom of the glass is the weight of all the liquid in a vertical cylinder, divided by the area of that cylinder …

so if you have a vertical cylinder of cross-section area A, what is the weight of water and mercury in that cylinder? :wink:
 
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