Gauss' Law Application Question

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SUMMARY

The discussion focuses on applying Gauss' Law to calculate the electric field generated by a linear charge distributed along a thin nonconductive rod. The charge density is given as λ = 10^-11 C/m and the rod length is L = 0.5 m. The correct formulation of Gauss' Law for this scenario is E = λ/(2πrε_0), where r = 0.1 m is the distance from the rod and ε_0 is the permittivity of free space. The length of the rod does not affect the electric field at the specified distance due to symmetry considerations.

PREREQUISITES
  • Understanding of Gauss' Law and its mathematical formulation
  • Familiarity with electric fields generated by line charges
  • Knowledge of the concept of charge density (λ)
  • Basic understanding of cylindrical symmetry in electrostatics
NEXT STEPS
  • Study the derivation of electric fields from line charges using Gauss' Law
  • Explore the concept of electric field lines and their behavior around charged objects
  • Learn about the permittivity of free space (ε_0) and its significance in electrostatics
  • Investigate applications of Gauss' Law in different geometrical configurations
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the application of Gauss' Law in calculating electric fields from line charges.

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Homework Statement


A linear charge lambda = 10^-11 C/m is uniformly distributed along a thin nonconductive rod of length L = 0.5 m.
Use Gauss' Law to calculate the field at a distance of r = 0.1 m from the charged rod.


Homework Equations


E.da = Q/ε_0

The Attempt at a Solution



Hi everyone,

Firstly, I assumed the rod was a line charge (as opposed to a cylinder, as it's so thin, yes?).

Then I rewrote Gauss' Law as: E_x.2πx_0.dz, where x_0 = 0.1 (... I chose a cylinder perpendicular to the rod as my Gaussian surface)
and the right-hand side as: λdz/ε_0
And so: E_x = λ/2πx_0ε_0

But I don't think this can be correct, as I haven't taken the length of the rod into account.
Can anyone please point me in the right direction?
 
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I understand that the radial distance from the rod is .1m. I suppose that they want the field somewhere toward he middle so that you may presume that the field lines are ⊥ still to the surface? If there is no particular location along the rod they want, then I'd say you can ignore the length through symmetry and use the charge per unit length in your answer.
 
It looks like you're doing it right. Length shouldn't matter in the problem. In your equation: E_x.2πx_0.dz = λdz/ε_0, your boundaries of integration should be 0 to the length of the Gaussian surface, L. You'll end up with E2πrL = λL/ε_0. Clearly, the L cancels out on both sides. Solving for E, E = λ/(2πrε_0)
 

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