Using Gauss' Law to Calculate electric field near rod.

Click For Summary
SUMMARY

This discussion focuses on applying Gauss' Law to calculate the electric field near a uniformly charged finite rod. The key equation used is the electric flux equation, Flux = EA = Q/ε. The user attempted to use E = λ L/(ε A) but encountered difficulties due to the lack of symmetry in the finite rod scenario, which complicates the evaluation of the electric field. The consensus is that symmetry arguments applicable to infinite rods do not hold for finite rods, making direct application of Gauss' Law challenging.

PREREQUISITES
  • Understanding of Gauss' Law and its mathematical formulation
  • Familiarity with electric flux concepts and calculations
  • Knowledge of symmetry arguments in electrostatics
  • Basic principles of electric fields and charge distributions
NEXT STEPS
  • Study the application of Gauss' Law for infinite charge distributions
  • Learn about electric field calculations for finite charged rods
  • Explore the concept of electric field lines and their relation to charge distributions
  • Investigate advanced techniques for evaluating electric fields without symmetry
USEFUL FOR

Students and educators in physics, particularly those studying electrostatics and electric fields, as well as anyone seeking to deepen their understanding of Gauss' Law applications.

Nathan B

Homework Statement


No variables, just a conceptual question.

Homework Equations


Flux = EA = Q/ε

The Attempt at a Solution


Given a uniformly charged rod of FINITE length, could we use Gauss' law for electric flux to calculate the field at a point p a distance x away from the rod, so long as the whole rod is enclosed and x lies on the surface area of the enclosing gaussian surface? I tried it with the equation E = λ L/(ε A), but it didn't work. I also found multiple different A's could be used, but none of them gave the right answer. Could someone please explain to me where I'm going wrong with this?
 
Physics news on Phys.org
Gauss's Law states that
$$\oint\mathbf{E}\cdot d\mathbf{a}=\frac{Q_{enc}}{\epsilon}$$
Normally, there is some kind of symmetry argument which can be made that allows us to know the direction of ##\mathbf{E}##. If the rod was infinitely long, then you could use mirror symmetry and translational symmetry to argue that only the radial component of ##\mathbf{E}## is non-zero at all points. In that case, the dot product ##\mathbf{E}\cdot d\mathbf{a}=E\hat{r}\cdot da\hat{r}=Eda## and we can evaluate the integral. In the case of a finite rod, do these symmetry arguments hold? If they don't then can you evaluate ##\mathbf{E}\cdot d\mathbf{a}##?
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
3K
Replies
3
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
9
Views
1K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
6
Views
2K