Gauss' Law Conclusion in Gravitational Fields

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SUMMARY

This discussion explores the application of Gauss' Law in gravitational fields, drawing parallels with electric fields. It confirms that within a solid conducting body, no charge exists inside the material, only on the outer surface, as dictated by Gauss' Law. When a point charge is introduced into a cavity, charge redistributes on the inner surface, resulting in no net electric field within the conductor. However, in gravitational fields, a point mass inside a spherical shell does not cause a redistribution of mass on the shell's surface, leading to the conclusion that gravitational fields behave differently than electric fields despite both adhering to Gauss' Law.

PREREQUISITES
  • Understanding of Gauss' Law in electrostatics
  • Familiarity with gravitational fields and their properties
  • Knowledge of spherical symmetry in physics
  • Concept of electric field and gravitational field interactions
NEXT STEPS
  • Study the implications of Gauss' Law in electrostatics and gravitation
  • Investigate the differences between electric and gravitational fields
  • Explore the concept of spherical shells in gravitational theory
  • Learn about the rigidity of materials and its effects on gravitational fields
USEFUL FOR

Physics students, educators, and researchers interested in the comparative study of electric and gravitational fields, particularly those focusing on Gauss' Law and its applications.

modulus
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I've been told that electric and gravitational fields have a lot in common, and both are practically analogous to each other. Also, the conclusions made through Gauss' Law apply just as well (analogously) to gravitational fields.



One of Gauss' Law's predictions is for a solid (conducting) charged body with a a cavity in it. According to it, no charge can exist inside the body...the only charge on it must exist on it's outer surface; that means no charge can exist on the inner surface. We get to that conclusion if we consider a Gaussian surface inside the body's material (not in the cavity).

But, if we introduce a point charge in the cavity, a charge develops on the inner surface, so that if we take a Gaussian surface in the body's material again (not in the cavity), there's no net electric field inside the body, and therefore, no net flux through the surface (and therefore, no net charge within the surface).


But, if we consider this for a gravitational field; we take a body with a cavity within it. For simplicity, I considered a spherical shell. I know that there's no gravitational field inside a shell. So, when I place a point mass inside the shell, why do we not observe any redistribution of the mass of the shell on the surface of the shell, so as to cancel out the gravitational field of the point mass (as we saw in the case of the point charge introduced in the cavity of the charged body). Or is there a tendency for a redistribution to take place...but it is not observable (or not possible, for that matter), because we consider the body to be rigid??
 
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modulus said:
One of Gauss' Law's predictions is for a solid (conducting) charged body with a a cavity in it. According to it, no charge can exist inside the body...the only charge on it must exist on it's outer surface; that means no charge can exist on the inner surface. We get to that conclusion if we consider a Gaussian surface inside the body's material (not in the cavity).
That's only true because the electrostatic field within a conductor must be zero. That goes beyond Gauss' law and has no parallel with gravity. (Gauss' law itself works just fine for both.)
 

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