(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A square plate of copper with 50.0-cm sides has no net charge and is placed in a region of uniform electric field of 80.0 kN/C directed perpendicularly to the plate. Find:

(a)the charge density of each face of the plate and

(b)the total charge on each face

2. Relevant equations

[tex]

E = \frac{\sigma}{2\epsilon {0}}

[/tex]

[tex]

\sigma = \frac{q}{a}

[/tex]

3. The attempt at a solution

I missed about a week due to unforeseen circumstances, so I'm struggling with this to catch up, but so far:

Area, converted to meters, is 0.25 m^2. Electric field, E, converted to nano units would be 80x10^-9. My understanding was that [tex]\Phi _E = 2EA[/tex] so [tex]\Phi _E = 2 \times \frac{\sigma}{2\epsilon {0}} \times \frac{q}{a}[/tex] which comes out to [tex]\Phi _E = 2 \times \frac{\sigma}{8.854\times(10^-12)}\times\frac{q}{0.50\times0.50} [/tex], however I'm a bit confused on this. How do I find the value of q, and am I correct in my setup such that [tex]\sigma[/tex] is setup within the second fraction, over 8.854*10^-12?

Any help is greatly appreciated

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# Homework Help: Gauss' Law & Surface Charge Density

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