fonseh
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?? What do you mean ?Mark44 said:The you look at a33 as a potential pivot.
?? What do you mean ?Mark44 said:The you look at a33 as a potential pivot.
Then you look at a33 as a potential pivot.fonseh said:?? What do you mean ?
Ray Vickson said:Generally, we start in column 1 and move the numerically largest value in that column to position (1,1), perhaps by swapping some row i and row 1. Then we do row operations to zero out the remaining elements in column 1.
Stephen Tashi said:As I recall, some computer implementations of Gaussian elimination that concern themselves with "numerical methods" begin by switching rows and columns so the element with largest absolute value (picked from the all elements in the entire matrix) is in position 1,1. They follow a similar policy to select subsequent pivots. However, for making theoretical conclusions about the algorithm of Gaussian elimination or prescribing how to do hand-calculations it is simpler to consider an algorithm where less freedom-of-choice is allowed in selecting pivots.
It would be challenging exercise in scholarship to determine if there is a "standard" definition of "Gaussian elimination" as a unique algorithm.
Or the notes in this picture is misleading ? It mentioned that the a11 or a22 is 0 , not when we pivot the a11 , the a21 and a31 is 0 ...Mark44 said:What is so difficult to understand here? In the visible image of your post, they swapped rows 1 and 2. As I mentioned before, this is one of the three possible row operations. The next operation is to replace row 2 by -.02/500 * R1 + R2. This is another of the three row operations I mentioned. The a2, 1 entry in the second row will be 0 after this operation.
fonseh said:Or the notes in this picture is misleading ? It mentioned that the a11 or a22 is 0 , not when we pivot the a11 , the a21 and a31 is 0 ...
It didnt mention about when after swapping row , the old a11 will become 0Ray Vickson said:The note you post is 100% clear, so you must be reading it incorrectly. Remember: after swapping rows 1 and ##i##, the old row ##i## becomes the new row 1, and vice-versa. The old ##a_{i1}## becomes the new ##a_{11}##, and the old ##a_{11}## becomes the new ##a_{i1}##.
fonseh said:It didnt mention about when after swapping row , the old a11 will become 0