Gaussian integral in two dimensions

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SUMMARY

The forum discussion centers on evaluating the Gaussian integral in two dimensions, specifically the expression \(\int_{-\infty}^{\infty}f(x,y)\ \exp(-(x^{2}+y^{2})/2\alpha)\ dx\ dy=1\). The key insight provided is the recommendation to convert the integral to polar coordinates for straightforward evaluation. The integral's outcome is contingent upon the function \(f(x,y)\) and the parameter \(\alpha\).

PREREQUISITES
  • Understanding of Gaussian integrals
  • Knowledge of polar coordinates in calculus
  • Familiarity with multivariable integration
  • Basic concepts of functions of two variables
NEXT STEPS
  • Study the properties of Gaussian integrals in higher dimensions
  • Learn about the transformation of integrals to polar coordinates
  • Explore the implications of different functions \(f(x,y)\) on the integral's evaluation
  • Investigate the role of the parameter \(\alpha\) in Gaussian distributions
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Mathematicians, physicists, and students studying multivariable calculus or statistical mechanics who are interested in evaluating Gaussian integrals and their applications.

spaghetti3451
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I am trying to evaluate the following integral.

##\displaystyle{\int_{-\infty}^{\infty}f(x,y)\ \exp(-(x^{2}+y^{2})/2\alpha)}\ dx\ dy=1##

How do you do the integral above?
 
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Hi, it seems evaluated jet ##=1##, depends what is ##f(x,y)## and ##\alpha##? You must to reformulate the question ...
 
failexam said:
I am trying to evaluate the following integral.

##\displaystyle{\int_{-\infty}^{\infty}f(x,y)\ \exp(-(x^{2}+y^{2})/2\alpha)}\ dx\ dy=1##

How do you do the integral above?
Convert to polar coordinates. Integration is straightforward.
 
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