Gaussian integration in infinitesimal limit

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The discussion focuses on calculating the probability of finding a particle within an infinitesimal interval using the wave function \Psi(x,0) = (2b/\pi)^{1/4}e^{-bx^2}. Participants explore the integral \int_0^{\Delta x} |\Psi(x,0)|^2 dx and the challenges of evaluating it with arbitrary limits. A key suggestion is to expand the wave function to first order in \Delta x, leading to the approximation P(\Delta x) = |\Psi(\Delta x)|^2 \Delta x. The concept of substituting multiplication for the integral in the infinitesimal limit is also discussed. This approach simplifies the calculation of probabilities in quantum mechanics.
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Homework Statement


Given the wave function of a particle \Psi(x,0) = \left(\frac{2b}{\pi}\right)^{1/4}e^{-bx^2}, what is the probability of finding the particle between 0 and \Delta x, where \Delta x can be assumed to be infinitesimal.

Homework Equations

The Attempt at a Solution


I proceed as I normally would when trying to obtain the probability of finding a particle within a certain interval, by calculating the integral ##\int_a^b |\Psi(x,0)|^2 dx##, where the limits here are ##a=0## and ##b=\Delta x##. I am stuck in trying to calculate the Gaussian with these limits. I know the answer in the infinite limit, but for abritrary limits one usually has to deal with error functions. What is the trick here with setting the upper limit to some assumed infinitesimal number? Would appreciate a hint!
 
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I think you just have to expand the wave function to first order in ##\Delta x## and then $$P(\Delta x)=|\Psi(\Delta x)|^2 \Delta x$$
Imagine the area under an infinitesimal interval, in this limit you can substitute multiplication for the integral. I am not entirely sure though.
See the post after this one.
 
Last edited:
Mr-R said:
Imagine the area under an infinitesimal interval, in this limit the integral can be substituted for a normal multiplication. I am not entirely sure though.
You worded that backwards. You can substitute multiplication for the integral:
$$\int_x^{x+dx} f(t)\,dt = f(x)\,dx$$
 
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Likes Mr-R
Cheers vela. Will edit it.
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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