Gauss's Law Problem: Electric Field Inside a Charged Cylinder

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SUMMARY

The discussion focuses on calculating the electric field inside a charged hollow metal cylinder with a central wire. The wire has a linear charge density of λ, while the cylinder has a net linear charge density of 2λ. Using Gauss's Law, the electric field strength inside the cylinder is derived as E = λ / (2πrε), where r is the radial distance from the center and ε is the permittivity constant. The cancellation of the electric field from the metal cylinder inside the hollow region is clarified, emphasizing that only the wire's charge contributes to the electric field within the cylinder.

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Homework Statement


A long, thin straight wire w/ linear charge density lambda runs down the center of a thin, hollow metal cylinder of radius R. The cylinder has net linear charge density of 2lambda. Assume lambda is positive. Find an expression for the electric field strength inside the cylinder.

I used a cylinder of length L for my gaussian surface:

the charge inside is lambda * L

E*2pir*L = lambda * L / permittivity constant

E= lambda/ (2pi*r*permittivity constant)

This is correct, but the thing I don't see is how the electric field from the metal cylinder cancels inside the cylinder. Wouldn't it only cancel at the very center?


Homework Equations





The Attempt at a Solution

 
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Oh... if I draw a gaussian surface inside, it only encloses the wire. I'm trying to fit my head around this.
 
Could someone please give a good explanation for this? Thanks
 

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