1. The question asks me to show that e^x is a solution of xy'' - (2x+1)y' + (x+1)y=0 and find the general solution. 2. I managed to simplify the equation to u''xe^(x) - u'e^(x) = 0 by letting y=ue^(x) and finding the differentials and substituting them in. I've then let z=u dz/du=u' and d^2z/du^2 = u'' so I get xe^(x)(d^2z/du^2) - e^(x)dz/du = 0 How would I solve this?