General Solution of PDE yux+xuy=yu+xex: Existence and Infinite Solutions

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Homework Help Overview

The discussion revolves around finding the general solution of a partial differential equation (PDE) given by yux + xuy = yu + xex. The original poster mentions a specific form of the solution and poses a question regarding the existence of solutions based on the initial conditions provided.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of characteristics as a potential approach to solve the PDE. Some express difficulty in finding the solution and seek further clarification on the problem's conditions and implications.

Discussion Status

There is an ongoing exploration of the problem, with some participants attempting the method of characteristics and sharing their findings. However, there is no consensus on the solution, and further clarification is sought regarding the initial conditions and their impact on the existence of solutions.

Contextual Notes

Participants note that the initial value φ has not been specified in a particular form, which raises questions about the existence of solutions. The implications of this condition are under discussion.

fderingoz
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find the general solution of yux+xuy=yu+xex ( the solution is in the form of u(x,y)=yex+f(y2-x2)ex )
if at first the value of u(x,y) on the upper half of hyperbola (that is y>=1) has been given as φ,show that if φ has not been given as a special form there is no solution.find that special form of φ and show there is infinite solution in this situation.
 
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thanks for your advice
i tried the method of characteristics,but i can not find the solution :blushing:
 
The characteristic equations are
<br /> \dot{x}=y,\quad\dot{y}=x,\quad\dot{u}=yu+xe^{x}<br />
then the characteristic are given as dy/dx=x/y. Then this integrates up to f(x,y)=C. Then use du/dx=\dot{u}/\dot{x} and integrate up.

Mat
 
i found the general solution of the equation. thanks for your helps
but i can't understand anything rest of the question.i am waiting for your helps.
 

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