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Geometric algebra cross product

  1. Feb 27, 2008 #1
    The problem statement, all variables and given/known data[/b]

    my text (Geometric Algebra for Physicists, by Doran and Lasenby), p. 69, deals with rotating frame {fsubk} (I assume in 3D)

    d/dt (fsubk) = omega X fsubk omega being angular velocity

    then

    omega X fsubk = (-I omega) dot fsubk = fsubk dot (I omega), where I is pseudoscalar and (I omega) is I think the geometric product of I and omega.

    I don't understand these algebraic steps. Can someone explain?

    I did follow earlier explanations of why with vectors a,b that a X b = -I(a wedge b)

    If I have posted this to the wrong forum, would the moderators kindly forward it to a more appropriate one?


    Thank you all very much!

    Ken Cohen
     
  2. jcsd
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