Geometric power series of f(x)=6/(2-x) c=1

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SUMMARY

The geometric power series for the function f(x) = 6/(2-x) centered at c=1 is derived by rewriting the function as 6(1/(2-x)). This is transformed into 6(1/(2(1-x/2))), which simplifies to 3(1/(1-x/2)). The resulting series converges for |x/2| < 1, leading to the series expansion 3Σ(x/2)^n for n=0 to ∞.

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Find the geometric power series for the given function:

f(x)=6/(2-x) c=1

I am stumped on this one. I've tried for an hour on this one with no luck. Could someone help?
 
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Write it as 6\left(\frac{1}{2-x}\right). You have to get rid of the 2 so write it as follows:

6\left(\frac{1}{2(1-\frac{x}{2})}\right) \rightarrow 3\left(\frac{1}{1-\frac{x}{2}}\right)
 
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