- #1

xeon123

- 90

- 0

I've these values:

Code:

```
# x y=f(x)
50 1957768251
100 3915542997
150 5873311096
500 19577709464
1000 39155455160
1500 58686574963
2000 78292255800
2500 97888617384
3000 117466340329
3500 137044056081
4000 156491263529
4500 176177759312
```

These values represents a straight line in a graph. Using the equation y=mx+b, and assuming b=0, I would like to know the slope of the straight line. Since, it's the m variable that gives me the slope, so,

[itex]m=\frac{y}{x}[/itex]Applying this equation, I get the results:

Code:

```
39155365
39155429
39155407
39155418
39155455
39124383
39146127
39155446
39155446
39155444
39122815
39150613
```

With these results, the slope is around 39000000? Shouldn't I get a more reasonable value, like 3?

What is the slope?

Thanks,