Giancoli Physics Book -- confused at meaning of "test charge" polarity

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SUMMARY

The discussion centers on the concept of "test charge" polarity as presented in the Giancoli Physics textbook. The equation E=F/q defines the electric field (E) as the force (F) on a small positive test charge (q) at rest. The confusion arises when the text states that if q is negative, F and E point in opposite directions, which seems contradictory since the test charge is typically considered positive. Clarification is provided that the sign of the test charge does not affect the calculation of E, and the relationship between force and electric field depends on the charge placed in the field.

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  • Understanding of electric fields and forces
  • Familiarity with the equation E=F/q
  • Knowledge of charge polarity (positive and negative)
  • Basic concepts of electrostatics
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kiwibird4
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In the giancoli physics textbook for engineers and scientists, it says
"E=F/q where E is the force on a small positive test charge at rest..."
Then about one paragraph later it proceeds to say
"If q is positive, F and E point in the same direction. If q is negative, F and E point in opposite directions".

I am confused. The text just said that the test charge in the E field equation will always be considered a -positive- charge, but then they talk about scenarios where it is negative, contradicting their own definition.
and if a test charge was then (contradicting their definition) negative, and "big" Q is negative, both the e-field and the force would be repulsive, pointing in the same direction whereas they said "if q is negative F and E point in opposite directions" (which would only be true if you assume the direction of the e field -where negative source charge has e field towards it- because you have a positive test charge)

I do not understand what I am missing so any help in clarifying this problem would be helpful.
 
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kiwibird4 said:
In the Giancoli physics textbook for engineers and scientists, it says
"E=F/q where E is the force on a small positive test charge at rest..."
In the above, the role of the "test charge" is to define and/or determine the electric field, E, at some location. Many books use a subscript of zero when referring to the test charge, i.e., q0. Although it's usual to use a small positive charge for the test charge, the sign is not important. You get the same result for E using either polarity.

In the following, the charge referred to has nothing to do with the above test charge.:

If you know the electric field, E, at some location, then the force, F, on an arbitrary charge, q, placed in that location is given by F = qE. Of course if q is negative, F and E are in opposite direction.
Then about one paragraph later it proceeds to say
"If q is positive, F and E point in the same direction. If q is negative, F and E point in opposite directions".

I am confused. The text just said that the test charge in the E field equation will always be considered a -positive- charge, but then they talk about scenarios where it is negative, contradicting their own definition.
and if a test charge was then (contradicting their definition) negative, and "big" Q is negative, both the e-field and the force would be repulsive, pointing in the same direction whereas they said "if q is negative F and E point in opposite directions" (which would only be true if you assume the direction of the e field -where negative source charge has e field towards it- because you have a positive test charge)

I do not understand what I am missing so any help in clarifying this problem would be helpful.
 

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