The probability of a silicon chip to be defect is .61 at the final production line.
What is the probability that exactly 6 of the 14 chips are NOT defect?
The Attempt at a Solution
P(A')=.39 (since we are going to be looking for the probability that we won't have a defective chip)
Now the probability that 6 of those 14 won't be defective is ???
If there is a 39% chance of success for the total 14 chips, how do I relate that to only 6 of them?
Help me visualize this since I am utterly horrible at statistics
<b>EDIT: Just found out this is a Binomial Distribution problem and found the answer by plugging and chugging the values into the formula</b>