Given a general probability, determining the probability in a set

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SUMMARY

The discussion centers on calculating the probability of exactly 6 out of 14 silicon chips being non-defective, given a defect probability of 0.61. The probability of a chip being non-defective is 0.39. The solution involves using the Binomial Distribution formula, specifically applying the combination formula 14C6 to determine the number of ways to choose 6 non-defective chips from a total of 14. The final answer is derived by substituting these values into the Binomial Distribution equation.

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  • Understanding of Binomial Distribution
  • Familiarity with combination calculations (nCr)
  • Basic probability concepts
  • Ability to perform calculations with probabilities
NEXT STEPS
  • Study the Binomial Distribution formula and its applications
  • Learn how to calculate combinations using the formula nCr
  • Explore examples of probability problems involving non-defective items
  • Practice solving real-world problems using probability distributions
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Students studying statistics, educators teaching probability concepts, and anyone interested in applying Binomial Distribution to real-world scenarios.

peterwilc
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Homework Statement



The probability of a silicon chip to be defect is .61 at the final production line.
What is the probability that exactly 6 of the 14 chips are NOT defect?

Homework Equations


The Attempt at a Solution



P(A)=.61
P(A')=.39 (since we are going to be looking for the probability that we won't have a defective chip)

Now the probability that 6 of those 14 won't be defective is ?

If there is a 39% chance of success for the total 14 chips, how do I relate that to only 6 of them?Help me visualize this since I am utterly horrible at statistics

<b>EDIT: Just found out this is a Binomial Distribution problem and found the answer by plugging and chugging the values into the formula</b>
 
Last edited:
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try use combination

14C6
 

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