1. The problem statement, all variables and given/known data Determine the voltage V0 in the following network if the impedance Z contains: a. a 0.5 mH inductor b.a 10 μF inductor [Broken] 2. Relevant equations Voltage division for 2 series resistors: (v in)(resistor/total series resistance) ZL = ωLj Zc = -1j/ωC Z = ZL + ZC + R Zmagnitude = (R2 + X2)1/2 θ = arctan(J/R) form Z = R + jx 3. The attempt at a solution ω = 377 ? Part a: ZL = 377 * (0.5 x 10-3) = 0.1885Ωj Z total = 100Ω + 0.1885Ωj Not sure what to do from here but I guess now try polar conversion, and doing that, Z basically rounds off to Z total = (100 ∠ 89.9 deg) Z(just the resistor in polar form) = (100 ∠ 90 deg) because the magnitude is 100 and arctan(100/0.000000001) = 90 degrees and I think V = 100 ∠ 0 deg, from the given source voltage. So I think V0t = (100 ∠ 90 deg)*((00 ∠ 90 deg)/(100 ∠ 90 deg)) = (100 ∠ 90 deg) (would be negative though, because the arrow is the opposite direction). but not sure. I know part B would basically be the same thing though.