Is the Formula for Voltage Drop Across Capacitor Opposite of Resistor?

[Joel Kee]

Homework Statement

I'm trying to calculate the voltage drop across a 60uF and a 30uF capacitor in series, powered by 60V. Is the formula for voltage drop across capacitor opposite of the formula for resistor, where resistor is R1=R1/(R1+R2) while capacitor is C1=C2/(C1+C2)?

Homework Equations

The Attempt at a Solution

 

[mfb]

Is the formula for voltage drop across capacitor opposite of the formula for resistor, where resistor is R1=R1/(R1+R2) while capacitor is C1=C2/(C1+C2)?

The symbols on the left side don't make sense. The right side is useful, but you should probably derive those equations to be sure.

 

[Joel Kee]

The symbols on the left side don't make sense. The right side is useful, but you should probably derive those equations to be sure.

My bad, the eqs are supposed to be multiplied with the total voltage.

 

[NascentOxygen]

It is far better that you be confident at deriving such formula yourself using basic knowledge.

The crux of the matter is that when connected to a source, equal amounts of charge are added to each of the series-connected capacitors.
Use this fact, together with Q = C·V, to confirm or disprove the formula you wrote.

 

[rude man]

My bad, the eqs are supposed to be multiplied with the total voltage.

Still your bad. R1=R1/(R1+R2) ? Etc.

 

[Joel Kee]

Still your bad. R1=R1/(R1+R2) ? Etc.

V1=[R1/(R1+R2)]V

My bad.