AC Cirucits - Impedance Values

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Discussion Overview

The discussion revolves around calculating various parameters of an AC circuit, including apparent power, reactive power, current magnitude, and impedance. The context is primarily homework-related, focusing on the application of formulas and concepts related to AC circuits.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • The initial calculations for apparent power, reactive power, and current magnitude are presented, with the apparent power calculated as 520.8333 VA, reactive power as 361.4448 VAR, and current as 4.34 A.
  • The impedance is initially calculated as 27.6498 ohms, leading to a phase angle of 43.95 degrees, suggesting an inductive circuit.
  • There is a challenge regarding the subtraction of complex numbers in polar form, with a conversion to rectangular form attempted.
  • A participant points out a typo in the calculations, which is acknowledged and corrected by the original poster.
  • Another participant suggests slight miscalculations in the original post, providing an alternative final impedance value of 21.60∠62.7 degrees.

Areas of Agreement / Disagreement

There is no clear consensus on the final impedance value, as participants present differing results. Some calculations are validated, while others are questioned, indicating ongoing uncertainty and refinement in the discussion.

Contextual Notes

Participants express uncertainty regarding the accuracy of the final impedance calculations, and there are unresolved aspects related to the handling of complex numbers and phase angles.

Joe85
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Homework Statement


For the circuit given in the power factor is 0.72 lagging and the power dissipated is 375 W.

12-jpg.jpg


Determine the:
(1) apparent power
(2) reactive power
(3) the magnitude of the current flowing in the circuit
(4) the value of the impedance Z and state whether circuit is inductive or
capacitive.

(1) Apparent power = True power / Power Factor (S=P/pf)

= 375 / 0.72

= 520.8333 VA

(2) Reactive Power = SQRT (apparent power^2) - (True Power^2)

= SQRT (520.8333^2)-(375^2)

= SQRT (130642.3264)

= 361.4448 VAR

(3) Magnitude of Current

Power= Voltage*Current *Power factor (P=V*I*pf)

375 = 120*I*0.72
I = P/(V*pf)
I = 375/(120*0.72)
I = 4.34 A

(4) Total ohms = Voltage/Current
= 120/4.34
= 27.6498 ohms
Phi= arccos(0.72) = 43.95
RT = 10 ohms

ZTotal= 27.6498∠43.95

Z = ZTotal - 10 | Cannot subtract complex numbers in polar form.

27.6498(Cos43.95+JSin43.95) = 19.9064 + J19.1898

(19.9064 + J19.1898) - 10 = 9.0964 + J19.1898

Z = SQRT (9.0964^2)+(19.1898^2) = 21.24

Phi = Arctan (19.1898/9.0964) = 64.64

Z = 21.24∠64.64 Lagging

Phase Angle Lagging - Circuit Inductive.

Homework Equations

The Attempt at a Solution



So i borrowed heavily from an older thread as my answers for 1 - 3 are identical. It's part 4 where I'm sturggling a bit. I followed the original thread, went away, refreshed my complex numbers knowledge and have come back with the above.

Would be greatful if someone could validate my answer or tell me if i have completely borked it up and offer some guidence.
 

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Last edited:
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The image you posted is too small to read from. Please upload a larger and clearer circuit diagram.
 
Updated
 
Joe85 said:
R = SQRT (9.0964^2)+(19.1898^2) = 21.24
Everything looks correct to me, except this typo:wink:.
 
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cnh1995 said:
Everything looks correct to me, except this typo:wink:.

Corrected and thank you very much.
 
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Slight miscalculations in the OP.

End result should be:

Z = 21.60∠62.7o
 

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