An unknown nucleus contains 71 neutrons and has twice the volume of the nickel http://www.webassign.net/www32/symImages/f/1/3dca243bf11d1adbce4ca198d1973f.gif nucleus. Identify the unknown nucleus.
r = (1.2X10^-15)(A^(1/3))
The Attempt at a Solution
I plugged 59 into the radius equation and got "4.6715957X10^-15 m"
I then plugged that r value into the volume equation which yielded "4.270555X10^-43"
Since the unknown nucleus is twice the volume of the Ni nucleus, I doubled that volume (getting 8.54111078X10^-43), plugged it into the volume equation to solve for r and got "5.8858 X 10^-15".
Then I plugged that into the original radius equation to solve for A. I keep getting "14.71" which doesn't make any sense to me.
Thanks in advance!
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