Given vectors how to find third equation

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Homework Help Overview

The problem involves finding the magnitude of the vector expression |2v - w| given the magnitudes of vectors v and w, and the angle between them. The context is vector mathematics, specifically focusing on vector operations and properties related to the dot product.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the dot product and the magnitudes of vectors, questioning how to derive the magnitude of the expression |2v - w| without knowing the individual vectors. There is an exploration of the definition of the magnitude of a vector in terms of the dot product.

Discussion Status

The discussion is ongoing with participants exploring different aspects of the problem. Some guidance has been provided regarding the use of the dot product to find the magnitude of the vector expression, but there is no explicit consensus on the next steps or a complete resolution.

Contextual Notes

There is a focus on understanding the properties of vectors and their magnitudes, with participants questioning the necessity of knowing the individual vectors to solve the problem. The discussion reflects a learning process around vector operations and definitions.

mill
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Homework Statement



If |v|=4, |w|=3 and the angle between and is pi/3, find |2v −w|

Homework Equations


##cosθ=\frac {v dot w} {|v||w|} ##

The Attempt at a Solution


## 6= v dot w ##

This is as far as I got. How would I find the separate values of v and w for the equation?
 
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mill said:

Homework Statement



If |v|=4, |w|=3 and the angle between and is pi/3, find |2v −w|

Homework Equations


##cosθ=\frac {v dot w} {|v||w|} ##

The Attempt at a Solution


## 6= v dot w ##

This is as far as I got. How would I find the separate values of v and w for the equation?

Very good! How is the absolute value of a vector defined with dot product by itself?
You do not need to know the individual vectors. You need the absolute value of 2v-w.

ehild
 
ehild said:
Very good! How is the absolute value of a vector defined with dot product by itself?
You do not need to know the individual vectors. You need the absolute value of 2v-w.

ehild

u dot u = ##|u|^2## so |u|= ##\sqrt {u dot u} ## ?

Possibly, that becomes |2v-w|=sqrt(something?) or would |?|(1/2)=|2v-w|

I'm afraid I don't see how things are connecting to the third equation though.

1/2 = (something analogous to u dot v)/|2v-w|?
 
Last edited:
mill said:
u dot u = ##|u|^2## so |u|= ##\sqrt {u dot u} ## ?
Start from that definition. What then is ##\sqrt{(2v-w) \cdot (2v-w)}##?
 
Got it, thanks.
 

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