What Is the Wavelength of the Signal Based on Goniometer Measurements?

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SUMMARY

The wavelength of the signal measured using goniometer measurements is determined by the distance moved through multiple intensity minima and maxima. Initially, the receiver is positioned at 8.4 cm, and after moving through 10 minima, it reaches 27.3 cm. The correct calculation for the wavelength (ƛ) is ƛ = (27.3 cm - 8.4 cm) / 5, resulting in a wavelength of 3.78 cm. This method accounts for the five complete wavelengths represented by the ten minima.

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  • Knowledge of intensity maxima and minima in wave patterns
  • Basic algebra for solving equations
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  • Learn about the principles of goniometry in wave measurements
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Mnemonic
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Homework Statement


Initially your receiver is positioned at a distance of 8.4 cm from the goniometer and recording a maximum intensity. You move it through 10 minimums in the intensity and then stop at the next maximum intensity. The receiver is now a distance of 27.3 cm from the goniometer.

What is the wavelength of the signal you have measured?

Homework Equations


ƛ/2=Distance between two maximums

The Attempt at a Solution


ƛ=2(27.3-8.4)cm
=37.8cm

It's that simple right?
I keep getting the wrong answer with this. What am I missing?
 
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Mnemonic said:

Homework Statement


Initially your receiver is positioned at a distance of 8.4 cm from the goniometer and recording a maximum intensity. You move it through 10 minimums in the intensity and then stop at the next maximum intensity. The receiver is now a distance of 27.3 cm from the goniometer.

What is the wavelength of the signal you have measured?

Homework Equations


ƛ/2=Distance between two maximums

The Attempt at a Solution


ƛ=2(27.3-8.4)cm
=37.8cm

It's that simple right?
I keep getting the wrong answer with this. What am I missing?
You are not taking into account that it was moved through many minima and maxima. You have calculated as though it was moved to the very next maximum.
 
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haruspex said:
You are not taking into account that it was moved through many minima and maxima. You have calculated as though it was moved to the very next maximum.

The wording in the question confused me. So you are saying that between each of the 10 minimums there was a maximum as well?
 
Mnemonic said:
The wording in the question confused me. So you are saying that between each of the 10 minimums there was a maximum as well?
That's the usual arrangement.
 
haruspex said:
That's the usual arrangement.

SO there are 5 complete wavelengths.

Therefore ƛ=(27.3-8.4)/5 cm
 
Mnemonic said:
SO there are 5 complete wavelengths.

Therefore ƛ=(27.3-8.4)/5 cm
That looks better.
 

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