You are welcome yuiop, I definitely can use some practice in checking mistakes in formulas as the formulas I write myself are often full of mistakes.
I attempted to generalize the formulas to obtain the proper velocity of a free falling observer wrt a local stationary observer, in the attempt to generalize the, what Pervect calls, 'the passionflower distance'. Then perhaps we can do the same thing but then for the 'Fermi distance'.
Apparently the velocity function can be parametrized, if I am not mistaken such thing was developed by Hartle (or perhaps he copied it before, I don't know that).
Basically the proper velocity wrt a local stationary observer of a radially free falling observer can be described as:
<br />
v=\sqrt {{\frac {{A}^{2}-g_{{{\it tt}}}}{{A}^{2}}}}<br />
where:
<br />
g_{{{\it tt}}}=1-2\,{\frac {m}{r}}<br />
In the case the free fall is from infinity A simply becomes 1.
In the case the free fall has an initial velocity then A is calculated as:
<br />
A={\frac {1}{\sqrt {1-{v}^{2}}}}<br />
Now, if we assume the formula below as given by yuiop is both correct and not an approximation:
<br />
\frac{dr}{dtau} = \sqrt{\frac{2m}{r} - \frac{2m}{R}} <br />
then there is a catch.
For A smaller than 1 the free fall starts from a given height. I was trying to obtain the correct formula in order to plug in the right A in such a case and here is where I got some surprises (I assume for the greater minds on the forum this is yet another demonstration of my lack of understanding). I did not succeed in expressing this in terms of r only. Initially I was trying to reason that if in some way I could 'subtract' the escape velocity at the given R and convert that into A I would get the expected results. But that did not work, it turns out that A is no longer constant during the free fall from a given height, we could express it in the following way to get the desired results, but it is ugly:
<br />
A = -{\frac {\sqrt { \left( -rR+2\,mR-2\,rm \right) R \left( -r+2\,m<br />
\right) }}{-rR+2\,mR-2\,rm}}<br />
This 'monstrosity' is not even real valued!
Now the interesting question is why, assuming again the formula based on this is exact, does the parameter depend on r? Perhaps I made a mistake or is perhaps the formula to obtain the proper velocity from a given R only an approximation?
For instance it is rather tempting to calculate A for a drop at h independently of r by using:
<br />
A=\sqrt {1-2\,{\frac {m}{h}}}<br />
The result is close to yuiop's formula but not identical. The 'shape' of the slabs look rather similar.