"An electron moves at 24.8m/s (N37.5E) and undergoes a constant 103m/s2 (E37.5S) acceleration for 3.02s what is the displacement?
0.5at^2 = d
The Attempt at a Solution
I calculated the displacements to be 74.896m (N37.5E) and 469.7006m (E37.5S). This is what I remember from high school, I can't remember the vector addition though. Would I just subtract to get 394 and then multiply by cos(37.5). Please help!