Gradients and Tangents to Level Curves

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SUMMARY

The gradient of the function f(x,y) = y - x at the point (2,1) is calculated as (-1, 1), represented as -i + j. A level curve is defined as a curve where all points have the same function value, which in this case corresponds to straight lines in R3. The gradient vector points in the direction of the fastest increase and is always perpendicular to the level curves. Understanding these concepts is essential for visualizing functions of multiple variables and their properties.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with vector notation
  • Knowledge of functions of two variables
  • Basic concepts of level curves in multivariable calculus
NEXT STEPS
  • Study the properties of gradients in multivariable calculus
  • Learn how to sketch level curves for different functions
  • Explore the concept of tangent planes to surfaces in R3
  • Investigate functions of three variables and their graphical representations
USEFUL FOR

Students studying multivariable calculus, educators teaching calculus concepts, and anyone interested in understanding gradients and level curves in mathematical functions.

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Homework Statement


Find the gradient of the function at the given point, then sketch the gradient together with the level curve that passes through the point.

f(x,y) = y - x (2,1)


Homework Equations



gradient of f = (df/dx)i + (df/dy)j

The Attempt at a Solution



df/dx = -1
df/dy = 1

gradient of f = (df/dx)i + (df/dy)j = -i + j

I don't really know where to go from here; what exactly is a level curve?
 
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Quincy said:

Homework Statement


Find the gradient of the function at the given point, then sketch the gradient together with the level curve that passes through the point.

f(x,y) = y - x (2,1)


Homework Equations



gradient of f = (df/dx)i + (df/dy)j
Keep in mind that these are really partial derivatives.
Quincy said:

The Attempt at a Solution



df/dx = -1
df/dy = 1

gradient of f = (df/dx)i + (df/dy)j = -i + j

I don't really know where to go from here; what exactly is a level curve?
A level curve is a curve for which all points on the curve have the same function value (z-value in this case. Since the graph of your function is a plane in R3, level curves will be straight lines.

If you are familiar with topographical maps, each curve shown on the map is a level curve. Each point on a given curve is at the same altitude.
 
Mark44 said:
A level curve is a curve for which all points on the curve have the same function value (z-value in this case. Since the graph of your function is a plane in R3, level curves will be straight lines.
So, the value of a function with two variables is the value of z? In other words, f(x,y) = z? What about functions with 3 variables (f(x,y,z))?
 
Typically w is used for functions of three variables, with w = f(x, y, z). In fact, the particular letter doesn't matter; it just has to be different from the others.
 
Mark44 said:
Typically w is used for functions of three variables, with w = f(x, y, z). In fact, the particular letter doesn't matter; it just has to be different from the others.
But a graph can only have 3 dimensions, x, y, and z, so what is w supposed to represent?
 
Quincy said:
But a graph can only have 3 dimensions, x, y, and z, so what is w supposed to represent?
It's true that we can't readily visualize a graph in more than 3 dimensions, but there's no reason we can't generalize the notion to higher dimensions.
 
Quincy said:
But a graph can only have 3 dimensions, x, y, and z, so what is w supposed to represent?
Well, a graph can have more than 3 dimensions, it is just hard to draw in a 3 dimensional space!

One important property of the gradient, by the way, is that it always point in the direction of fastest increase and is always perpendicular to "level curves" (or level surfaces for functions of two dimensions). If you know a vector perpendicular to a line at a point, it is easy to give the equation of the line perpendicular to that vector and so tangent to the curve. And, of course, it is easy to use a vector perpendicular to a surface, at a point, to find the tangent plane to the surface at that point.
 

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