Grand Canonical Partition Function for Simple System

[PitchAintOne]

Homework Statement

I would like to calculate the grand canonical partition function (GCPF) for a system in which there are are $m$ lattice sites. A configuration may be specified by the numbers $(n_1, n_2, ... , n_m)$, where $n_k = 1$ if a particle occupies site $k$ and $n_k = 0$ if no particle occupies site $k$. Occupied sites have an associated energy $\epsilon$ (constant) and unoccupied sites have zero associated energy.

Homework Equations

The general form of the GCPF in my book (Chandler) is given like this:

$$\Xi = \sum_{\nu} e^{ -\beta E_{\nu} + \beta \mu N_{\nu} }$$

where $\nu$ indicates a summation over all states. (I am confused as to what, exactly, is meant by a "state" in the context of this problem.)

The Attempt at a Solution

For a given state $j$ the number of particles is given by $N_j = \sum_{j=1}^{m} n_i$ (summing over all sites). For the same state $j$ the energy is given by $E_j = \epsilon \sum_{i=1}^{m} n_i$.

I'm unsure of the correct direction from here. Inserting the expressions for $N_j$ and $E_j$ into $\Xi$ creates a mess of summations. Is that the only way? Is it simplify-able?

I feel that I should be able to calculate the GCPF for just one site and then extend the result to $m$ sites since the sites are independent of one another. Is this possible? If so, how?

Thank you all.

 

[clamtrox]

A state is a set of occupation numbers (n_1,n_2,...,n_m) so when you sum over all possible states, you sum over configurations (0,0,...,0), (1,0,0,...,0), ... , (1,1,...,1). Luckily the system is quite symmetric, so you do not need to sum the states one by one. Instead, you can write the sum over the number of occupied sites like so:

$\sum_{\nu} \rightarrow \sum_{n=0}^{m} \omega(n)$

where $\omega(n)$ is the density of states, ie. the number of microstates (n1,n2,...,nm) corresponding to the macrostate.