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Graph displacement as function of time

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  1. Feb 2, 2016 #1
    1. The problem statement, all variables and given/known data
    let there be ##\beta(t+\tau)^{-2}e^{-3}cos(at^{3})## where ##\beta##, ##\tau## and ##a## are constants

    2. Relevant equations

    ##\beta(t+\tau)^{-2}e^{-3}cos(at^{3})##

    3. The attempt at a solution

    I know the graph is going up and down exponential but how can I draw it more accurately?
     
  2. jcsd
  3. Feb 2, 2016 #2

    RUber

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    Find some benchmarks to plot...i.e. t = 0, ##t^3 =## some multiple of ##\pi/a##.
    Once you have some of those magnitudes and periods, you should have all you need.
     
  4. Feb 2, 2016 #3
    I have a lot of constant so rather than at ##t=0## the answer says something like slope of about ##\frac{1}{t^2}## and frequency of about ##t^3## how did the get to it?
     
  5. Feb 2, 2016 #4

    RUber

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    Change all your constants to 0 or 1 (whichever makes more sense), then look at the remaining function of t.
    What is the frequency of cosine?
     
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