The discussion focuses on graphing the conic section represented by the equation x² - 4y² + 2x + 8y - 7 = 0. The correct transformation of the equation leads to (x + 1)² = -4(y - 2), indicating a vertex at (-1, 2) and a directrix of y = 2. The parameter p is determined to be -1, confirming the conic's properties. Participants emphasize the importance of correctly completing the square in both x and y to derive accurate results.
PREREQUISITESStudents studying conic sections, mathematics educators, and anyone interested in graphing parabolas and understanding their geometric properties.
No, that's completely wrong! What happened to the y2 in the original equation? Try completing the square in y again!duki said:Homework Statement
graph the following:
Homework Equations
[tex]x^2-4y^2+2x+8y-7=0[/tex]
The Attempt at a Solution
So far I've gotten to [tex](x+1)^2 = -4(y-2)[/tex]
If that's right, I have p = -1 and v = (-1 , 2) and directrix: y=2. Could someone double check me to see if I'm doing it right?
Thanks