Graphing Conics: Finding the Vertex, Directrix, and Focus of x^2-4y^2+2x+8y-7=0

[duki]

Homework Statement

graph the following:

Homework Equations

$$x^2-4y^2+2x+8y-7=0$$

The Attempt at a Solution

So far I've gotten to $$(x+1)^2 = -4(y-2)$$
If that's right, I have p = -1 and v = (-1 , 2) and directrix: y=2. Could someone double check me to see if I'm doing it right?

Thanks

 

[HallsofIvy]

Homework Statement

graph the following:

Homework Equations

$$x^2-4y^2+2x+8y-7=0$$

The Attempt at a Solution

So far I've gotten to $$(x+1)^2 = -4(y-2)$$

No, that's completely wrong! What happened to the y² in the original equation? Try completing the square in y again!

If that's right, I have p = -1 and v = (-1 , 2) and directrix: y=2. Could someone double check me to see if I'm doing it right?

Thanks