Graphing (Precalculus) Homework: Transforming Functions for y=(x-3)^2 and y=x^n

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SUMMARY

The discussion focuses on transforming the function y=(x-3)^2 using the basic function y=x^2 as a reference. The transformation involves a horizontal shift of the graph of y=x^2, specifically moving it three units to the right to achieve the vertex at (3, 0). The key operations include recognizing that modifications to the input x affect the horizontal position, while changes to the output y affect the vertical position. Understanding these transformations is essential for accurately sketching the graph of y=(x-3)^2.

PREREQUISITES
  • Understanding of basic function graphs, specifically y=x^2
  • Knowledge of function transformations, including horizontal and vertical shifts
  • Familiarity with the concept of vertices in parabolic functions
  • Ability to sketch graphs of polynomial functions
NEXT STEPS
  • Study the properties of polynomial functions, focusing on y=x^n
  • Learn about function transformations, including translations and reflections
  • Practice sketching graphs of transformed functions using various values of n
  • Explore the implications of vertex shifts in quadratic functions
USEFUL FOR

Students studying precalculus, educators teaching graphing techniques, and anyone seeking to improve their understanding of function transformations in mathematics.

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Homework Statement


Sketch the graph of the function y=(x-3)^2 by transforming the graph of an appropriate function of the form y=x^n



Homework Equations


y=(x-3)^2, y=x^n


The Attempt at a Solution


Precisely speaking, I am just totally confused with what the question is asking. i mean i know how to graph y=(x-3)^2 bit idk what the y=x^n is about. thanks so much!
 
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If you look carefully at the exponents, you might guess that they mean n = 2.
So the question is, through what (geometric) operation(s) can you obtain the graph of (x - 3)3 from that of x2?

Since x2 is a basic graph (you should be able to draw it by heart), given this set of operations you can also draw (x - 3)2.
 
Generally speaking, anything that is done to x before the "basic function" is a change in x and so changes the graph horizontally. Anything that is done after the "basic function" is a change in y and so changes the graph vertically.

Here, the "basic function" is [itex]x^2[/itex] and [itex](x- 3)^2[/itex] is just [itex]x^2[/itex] with 3 subtracted from x before the square. The graph of [itex]y= x^2[/itex] itself is a parabola with vertex at (0, 0). x- 3= 0 when x= 3. The graph of [itex]y= (x- 3)^2[/itex] is the graph of [itex]y= x^2[/tex] shifted three places to the right- a parabola with vertex at (3, 0).[/itex]
 

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