Gravimetric chemistry equation balance problem

[Another]

Q : sample 0.2795 g containing only C₆H₆Cl₆ (Mw = 209.8) and C₁₄H₉Cl₅ (Mw = 354.5)
precipitate AgCl 0.7161 g (Calculate %(C₆H₆Cl₆) and %(C₁₄H₉Cl₅) in sample)

AgCl has 143.3 g/mol and 4.997 x 10^-3

I get
0.2795 g = weight of (C₆H₆Cl₆) + weight of (C₁₄H₉Cl₅)

mol of AgCl = mol of (C₆H₆Cl₆) + mol of (C₁₄H₉Cl₅)

where weight of (C₆H₆Cl₆) = x

4.997 x 10^-3 = x/(Mw of C₆H₆Cl₆) + (0.2795 - x)/(Mw of ₁₄H₉Cl₅)

I have calculated and my answer incorrectly

(The correct answer is 26.01 % (C₆H₆Cl₆) and 77.99% (₁₄H₉Cl₅))

please help me !

 

[Borek]

mol of AgCl = mol of (C₆H₆Cl₆) + mol of (C₁₄H₉Cl₅)

Doesn't look correct to me.