Gravitational ep in a uniform field

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SUMMARY

The discussion focuses on calculating the change in gravitational potential energy for a 10.0 kg box sliding down a 15.0 m ramp inclined at 20.0 degrees, with a frictional force of 40.0 N. The initial attempt used the work formula W=Fdcos(theta), yielding 563.8 J, but the correct change in gravitational potential energy is -503 J. The solution involves using the formula V = mgh to determine the initial height of the box.

PREREQUISITES
  • Understanding of gravitational potential energy (V = mgh)
  • Knowledge of trigonometric functions, specifically cosine
  • Familiarity with the concept of work and forces
  • Basic physics principles related to inclined planes
NEXT STEPS
  • Calculate gravitational potential energy changes in various scenarios
  • Explore the effects of different angles on inclined plane problems
  • Learn about the role of friction in energy calculations
  • Study the relationship between work, energy, and power in physics
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Students studying physics, particularly those focusing on mechanics and energy concepts, as well as educators looking for practical examples of gravitational potential energy calculations.

kelly242
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Homework Statement


A 10.0 kg box is slid down15.0 m along a 20.0o ramp. The force of friction is 40.0 N. What is the change in the gravitational potential energy of the box?

Homework Equations



W=Fdcos of theta

The Attempt at a Solution


W=(40 N)(15 m)(cos 20)
=563.8J
The actual answer is -503 J...
 
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Try:

V = mgh

Then just figure out what the initial height is.
 

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