Gravitational Forces acting on a satellite

  • Thread starter Lyphta
  • Start date
  • #1
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[SOLVED] Gravitational Forces

Homework Statement


A 1000 kg weather satellite is orbiting the earth at a constant speed. It is 500 km above the earth's surface. The earth has a mass of 5.976 x 10^24 kg and a radius of 6370 km. (a) How much gravitational force exists between the Earth and the satellite? (b) How long does it take the satellite to go around the Earth once? (c) How are is that (measured in meters)? (d) how fast is the satellite moving (in m/sec)?


Homework Equations


F=G(m1 m2)/r^2
C=2πr
v=rω

The Attempt at a Solution


(a) F=6.67 x 10^-11 N.m^2/kg^2)((1000kg)(5.976 x 10^24 kg)/6870000 m^2)
= 8445.5 N

(b) I have no idea how to do this one with the numbers that was given... the answer is 94.49 min...

(c) C=2(π)(6870000 m)
= 4.32 x 10^7m

(d) all I know is to do v=rω. But I don't know what to plug in.... the answer is 7617.1 m/sec
 
Last edited:

Answers and Replies

  • #3
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i know that stuff on the website. the only thing i dont understand is how to apply it to part b and d because i'm not sure of how to convert them into minutes. and without that, i can't figure out how to find the velocity...
 
  • #4
Tom Mattson
Staff Emeritus
Science Advisor
Gold Member
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I would do part d before doing part b, actually. Since you already know the force acting on the satellite, you can use Newton's second law F=ma. The acceleration a is centripetal accleration, the expression for which is given on the site provided by Kurdt.

Do you see what I mean?
 
  • #5
11
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oh yeah i got it! thanks!
 

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