Gravitational Forces between planets/objects

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SUMMARY

The gravitational acceleration at the surface of planet X is 12.0 m/s², with a radius of 67,400 km. To determine the altitude above planet X where an object's weight equals that on Earth's surface, the mass of planet X was calculated to be approximately 8.17e26 kg. By equating the gravitational forces and solving the equations, it was found that the altitude h is approximately 7200 km. This solution effectively utilizes the gravitational equations and constants to arrive at the correct altitude.

PREREQUISITES
  • Understanding of gravitational force equations, specifically W=(G*m_1*m_2)/r²
  • Knowledge of gravitational acceleration and its relation to mass and radius
  • Familiarity with algebraic manipulation of equations
  • Basic understanding of planetary mass calculations
NEXT STEPS
  • Study the derivation of gravitational force equations in classical mechanics
  • Learn about the implications of gravitational acceleration on different celestial bodies
  • Explore methods for calculating the mass of celestial objects using gravitational data
  • Investigate the effects of altitude on gravitational force and weight
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces, astrophysics enthusiasts, and educators teaching gravitational concepts in higher education.

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Homework Statement


The gravitational acceleration at the surface of planet X is 12.0 m/s2, and the radius of the planet is 67,400 km. The altitude above the surface of planet X, at which the weight of a body is equal to that on the surface of the Earth, in km, is closest to what value ?




Homework Equations



W(weight of object at the Earth surface)=(G*m_1*m_2)/r^2
m_1--- the mass of the object
m_2----- the mass of the Earth

W(weight of the object above the planet X)=(G*m_1*m_3)/(r+h)^2
m_3 ----the mass of the planet X
m_1----the mass of the object

Looking for h----the altitude at which the object weights the same as at the surface of the Earth;


The Attempt at a Solution


Not sure which equations to use or how to relate the correct equations to each other;but:

W(of the object at the Earth's surface)= 9.8*m_1
W(of the object at the X planet's surface)= 12*m_1

Possibly substitute 12*m_1 into W=(G*m_1*m_3)/(r+h)^2
Then m_1 will cancel out; but have two unknowns left: m_3 and h...not sure how to go from here. Please help.
 
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Hint: G\dfrac{m_1 m_2}{r^{2}} = m_2 g is what is used to caluclate the approximation F=mg at earth.
 
I understand the formula, but what do I need it for?
m_1 wil cancel out if I set both equations equal to each other. But I still need m_3 inorder to find h. Please help.

I went to the tutoring center in my college, and even they were not able to help me solve this problem( after being there for 2 hours :( )

How do I ( if I can at all) figure out the mass of the planet X? Or maybe there is another way to go around it, and I just do not see it. Not sure. Really need help.
 
here is what I came up with:

1. a=g=12=(G*m_3)/r^2

m_3(mass of the planet X)= 8.17e26 kg

2. Then:
W(weight of the object above the planet X)=(G*m_1*m_3)/(r+h)^2

9.8*m_1=W=(G*m_1*m_3)/(r+h)^2...where m_1 cancels out, and we are left with following:

9.8=(G*m_3)/(r+h)^2
9.8=[(6.67*10^(-11))*8.17e26 kg]/[67400000m+ h]^2 ... solvinf gor h:
7.46e7=67400000+h
h= 7.2e6 m or 7200 km...is it correct? Please let me know, and if it...then thank you very much for your help :)
 
This was exactly what i was hinting for :) Good work!
 

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