Gravity and mass of two objects

  • Thread starter Thread starter AnkhUNC
  • Start date Start date
  • Tags Tags
    Gravity Mass
AnkhUNC
Messages
89
Reaction score
0

Homework Statement


There are two masses of unknown weight on a straight line with a small red particle between them. At x (Measured from the center of m1) = .515 the particle does not move. What is the ratio of the two masses? i.e. m2/m1.


Homework Equations





The Attempt at a Solution



So do I use F = G*m1*m2/r^2? Since the particle isn't moving then the forces are balanced does this mean F = 0 then?
 
on Phys.org
Hi AnkhUNC! :smile:
AnkhUNC said:
So do I use F = G*m1*m2/r^2?

Not exactly … you use F1 = G*m*m1/r1^2 and F2 = G*m*m2/r2^2 and F1 = F2.

Hint: what is the relationship between m1/m2 and r1/r2? :smile:
 
On the right side the min x = .043 on the left side the max is .957. It starts out at .5 though which is in the middle so I guess <- is 0 and -> is 1.

r1/r2 = 1, they're both .5 away so .5/.5 = 1.

m2 is greater than m1 because the attraction is stronger so does m2 = .515 and m1 = .485?
 
So F = G*m*m1*m2?
 
AnkhUNC said:
On the right side the min x = .043 on the left side the max is .957. It starts out at .5 though which is in the middle so I guess <- is 0 and -> is 1.

Sorry, AnkhUNC, but I honestly have no idea what this means. :confused: :cry:
tiny-tim said:
F1 = G*m*m1/r1^2 and F2 = G*m*m2/r2^2 and F1 = F2.

Hint: divide F1 by F2. :smile:
 

Similar threads

Replies
14
Views
3K
Replies
20
Views
3K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K